Modeling tortuosity to directional surveys
30 March 2013 Hi folks,Here's a challenge for you all.
Looking at some of the surveys for recent wells, and particularly vertical wells, it seems possible that the BHAs are producing spiraled well-bores that we cannot readily identify with MWD survey QA/QC standard techniques.
By analyzing torque and Drag data of actual versus theoretical there are sections where the friction factors change for no apparent reason. I looked at ways to apply a factor to the well path to simulate the actual surveys and bring friction factors back into line.
The standard formula for applying tortuosity I believe is;
Ť = (((Summation between n and j=1)(DL^2)) - ((Summation between m and i=1)(DL^2))) / MDj - MDi
This, however gives a very conservative result.
If a sine wave is applied, using the magnitude (amplitude) and period (wavelength) specified, then the angle change would be; M sin (MD/p)2p
Where M is measured depth, p is the period and M the magnitude of the maximum variation of angle to be applied to the inclination and azimuth value.
The only problem I have so far it that if the inclination is modified below zero, the equations don´t work.
Similarly, the survey depth should not be an exact multiple of the period as then sin(MD/p)2p = 0
New inclination and azimuth are as follows;
Inc2 = a a1
Azi2 = Azi1 a1 crv (cross vertical correction).
I applied the equations above and made a rough Excel sheet to convert actual surveys to correct to include the sine wave.
Magically - the corrected surveys normalise the friction factors and bring the Torque and drag model into line.
The grey areas are as follows;
- Amplitude of the sine curve - can we simply apply stabilizer size minus tubular size (similar as the calculations for minimum effective hole diameter.
- Period of the sine curve - my initial suggestion is as per stabilizer spacing (points on maximum diameter and so likely to follow a straighter trajectory); added to this is the effect of stabilizer blade length.
- How to eliminate the effect on negative inclination (though I suspect this is a matter of applying Algebraic logic to the argument).
- When the MD of the survey is an exact multiple of the period - how to avoid. As per point above, I suspect this can be cured by creative nesting in the calculation. (sin(MD/p)2p then becomes zero).
Does anyone have any suggestions...???
Thanks
Hendo
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